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Thread: clCreateProgramWithSource - could be a file?

  1. #1
    Junior Member
    Join Date
    Apr 2013

    clCreateProgramWithSource - could be a file?

    Hi there,

    I was studying opencl until I see the clCreateProgramWithSource(). This function uses, as a parameter, a string which is the kernel source code to be built. But, is there any specific reason why not get a file path and read it? Any security reason?

    Every time that I want to use a kernel program I need to read the kernel file, then pass its content to a buffer. So, it could be better if opencl has support to read files.

  2. #2
    Senior Member
    Join Date
    Oct 2012

    Re: clCreateProgramWithSource - could be a file?

    It shouldnt be that hard for you to load a file from disk on your pc. But every opencl vendor (from a like amd to z like zfx) has to write a fileload into ther opencl implementation.

  3. #3
    Junior Member
    Join Date
    Apr 2013

    Re: clCreateProgramWithSource - could be a file?

    If the opencl specification said that the parameter of clCreateProgramWithSource should be a file instead of string, all vendors should implement it. I think that use a file as a parameter will be better and simple than put a string...I know that it is simple to load a file and pass its string, but pass the file is
    more intuitive than the first option.

  4. #4

    Re: clCreateProgramWithSource - could be a file?

    This is because not everyone loads kernel sources from files.

    If clCreateProgramWithSource() only took a file name it would prevent applications from programmatically creating and using kernel source strings at run-time. The only option in that case would be to create the string, write it to a temporary file, then reload the file again (quite inefficent).

    In most programming languages it only takes a couple lines of code to open a file and read its contents into a string.

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